Prove that: (A+2B).(2A-3B) = 2A^2 + ABcos(theta) -6B^2

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Prove that: (A + 2B).(2A – 3B) = 2A^2 + AB cos (theta) – 6B^2
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Prove that: (A + 2B).(2A – 3B) = 2A^2 + AB cos (theta) – 6B^2 Prove that: (A+2B).(2A-3B) = 2A^2 + ABcos(theta) -6B^2 August 27, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
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