pKa1 =6.35; pKa2 ​= 10.33; log3=0.477

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50 mL of 0.05 M Na2CO3 is titrated against 0.1 M HCl. On adding 40 mL of HCl, pH of the solution will be [Given for H2CO3, pKa1 =6.35; pKa2 ​= 10.33; log3=0.477, log2=0.30]
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Nov
50 mL of 0.05 M Na2CO3 is titrated against 0.1 M HCl. On adding 40 mL of HCl, pH of the solution will be [Given for H2CO3, pKa1 =6.35; pKa2 ​= 10.33; log3=0.477, log2=0.30] 50 mL of 0.05 M Na2CO3 is titrated against 0.1 M HCl. On adding 40 mL of HCl log2=0.30] pH of [...]
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Tags: 50 mL of 0.05 M Na2CO3 is titrated against 0.1 M HCl. On adding 40 mL of HCl , log2=0.30] , pH of the solution will be [Given for H2CO3 , pKa1 =6.35; pKa2 ​= 10.33; log3=0.477 ,