PD ⊥ QR such that D lies on QR . If PQ = a

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11. In ∆ PQR, PD ⊥ QR such that D lies on QR . If PQ = a, PR = b, QD = c and DR = d, prove that (a + b) (a – b) = (c + d) (c – d).
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11. In ∆ PQR, PD ⊥ QR such that D lies on QR . If PQ = a, PR = b, QD = c and DR = d, prove that (a + b) (a – b) = (c + d) (c – d). 11. In ∆ PQR PD ⊥ QR such that D lies on [...]
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Tags: 11. In ∆ PQR , PD ⊥ QR such that D lies on QR . If PQ = a , PR = b , prove that (a + b) (a – b) = (c + d) (c – d). , QD = c and DR = d ,