PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM = 1/2(∠Q – ∠R).

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7. In the given figure, ∠Q > ∠R, PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM = 1/2(∠Q – ∠R).
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7. In the given figure, ∠Q > ∠R, PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM = 1/2(∠Q – ∠R). ∠Q > ∠R 7. In the given figure PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM = 1/2(∠Q – ∠R). June 30, 2021 Category: Chapter [...]
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Tags: ∠Q > ∠R , 7. In the given figure , PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM = 1/2(∠Q – ∠R). ,