P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD)

Sahay Sir > Question Answers > P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD)
4. In Fig. 9.16, P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD)
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4. In Fig. 9.16, P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD) 4. In Fig. 9.16 P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ [...]
Posted in: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 ,
Tags: 4. In Fig. 9.16 , P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD) ,