Obtain the binding energy of the nuclei .26Fe56 and .83Bi209 in units of MeV form the following data: m (.26Fe56)= 55.934939 a.m.u.

Sahay Sir > Question Answers > Obtain the binding energy of the nuclei .26Fe56 and .83Bi209 in units of MeV form the following data: m (.26Fe56)= 55.934939 a.m.u.
Obtain the binding energy of the nuclei .26Fe56 and .83Bi209 in units of MeV form the following data: m (.26Fe56)= 55.934939 a.m.u. , m=(.83Bi209)= 208.980388amu. Which nucleus has greater binding energy per nucleon?
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Sep
Obtain the binding energy of the nuclei .26Fe56 and .83Bi209 in units of MeV form the following data: m (.26Fe56)= 55.934939 a.m.u. , m=(.83Bi209)= 208.980388amu. Which nucleus has greater binding energy per nucleon? m=(.83Bi209)= 208.980388amu. Which nucleus has greater binding energy per nucleon? Obtain the binding energy of the nuclei .26Fe56 and .83Bi209 in units [...]
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Tags: m=(.83Bi209)= 208.980388amu. Which nucleus has greater binding energy per nucleon? , Obtain the binding energy of the nuclei .26Fe56 and .83Bi209 in units of MeV form the following data: m (.26Fe56)= 55.934939 a.m.u. ,