M(229 Pa 91) = 229.032089 amu

Sahay Sir > Question Answers > M(229 Pa 91) = 229.032089 amu
Consider the β decay 198 Au→ 198 Hg+ β − + v , where 198 Hg is a mercury nucleus in an excited state of energy 1.088 MeV above the ground state. The atomic mass of 198 Au is 197.968233u and that of 198 Hg is 197.96676u and (1u=931 MeV/c 2 ). Choose the correct statement.
12
Sep
Consider the β decay 198 Au→ 198 Hg+ β − + v , where 198 Hg is a mercury nucleus in an excited state of energy 1.088 MeV above the ground state. The atomic mass of 198 Au is 197.968233u and that of 198 Hg is 197.96676u and (1u=931 MeV/c 2 ). Choose the correct [...]
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Tags: Consider the β decay 198 Au→ 198 Hg+ β − + v , M(229 Pa 91) = 229.032089 amu , M(230 U 92) =229.033496 amu , m(n) = 1.008665 amu , m(p) = 1.007825 amu. , Show that 230 U 92 does not decay by emitting a neutron or proton. Given: M (229 U 92) =230.033927 amu ,
Show that 230 U 92 does not decay by emitting a neutron or proton. Given: M (229 U 92) =230.033927 amu, M(230 U 92) =229.033496 amu, M(229 Pa 91) = 229.032089 amu, m(n) = 1.008665 amu, m(p) = 1.007825 amu.
12
Sep
Show that 230 U 92 does not decay by emitting a neutron or proton. Given: M (229 U 92) =230.033927 amu, M(230 U 92) =229.033496 amu, M(229 Pa 91) = 229.032089 amu, m(n) = 1.008665 amu, m(p) = 1.007825 amu. M(229 Pa 91) = 229.032089 amu M(230 U 92) =229.033496 amu m(n) = 1.008665 amu [...]
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: M(229 Pa 91) = 229.032089 amu , M(230 U 92) =229.033496 amu , m(n) = 1.008665 amu , m(p) = 1.007825 amu. , Show that 230 U 92 does not decay by emitting a neutron or proton. Given: M (229 U 92) =230.033927 amu ,