l = 0 m = 0 and s = +1/2 correspond to the most loosely bound

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Which one is a wrong statement (a) Total orbital anular momentum of electron in ‘s’ orbital is equal to zero (b) An orbital is designated by three quantum numbers while an electron in an atom designated by four quantum numbers.
29
Nov
Which one is a wrong statement (a) Total orbital anular momentum of electron in ‘s’ orbital is equal to zero (b) An orbital is designated by three quantum numbers while an electron in an atom designated by four quantum numbers. ground state electron of which one of the following atoms l = 0 m = [...]
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Tags: ground state electron of which one of the following atoms , l = 0 m = 0 and s = +1/2 correspond to the most loosely bound , The set of quantum numbers n = 4 ,
The set of quantum numbers n = 4 , l = 0 m = 0 and s = +1/2 correspond to the most loosely bound , ground state electron of which one of the following atoms
29
Nov
The set of quantum numbers n = 4 , l = 0 m = 0 and s = +1/2 correspond to the most loosely bound , ground state electron of which one of the following atoms ground state electron of which one of the following atoms l = 0 m = 0 and s = [...]
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: ground state electron of which one of the following atoms , l = 0 m = 0 and s = +1/2 correspond to the most loosely bound , The set of quantum numbers n = 4 ,