Kp ​= 7 × 10^−2. If 0.50 mole of hydrogen and 1.0 mole of sulfur are heated to 87^∘C in 1.0 L vessel

Sahay Sir > Question Answers > Kp ​= 7 × 10^−2. If 0.50 mole of hydrogen and 1.0 mole of sulfur are heated to 87^∘C in 1.0 L vessel
At 87^∘C, the following equilibrium is established H2 ​(g) + S(s) ⇌ H2S(g), Kp ​= 7 × 10^−2. If 0.50 mole of hydrogen and 1.0 mole of sulfur are heated to 87^∘C in 1.0 L vessel, what will be the partial pressure of H2S at equilibrium?
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Nov
At 87^∘C, the following equilibrium is established H2 ​(g) + S(s) ⇌ H2S(g), Kp ​= 7 × 10^−2. If 0.50 mole of hydrogen and 1.0 mole of sulfur are heated to 87^∘C in 1.0 L vessel, what will be the partial pressure of H2S at equilibrium? At 87^∘C Kp ​= 7 × 10^−2. If 0.50 [...]
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Tags: At 87^∘C , Kp ​= 7 × 10^−2. If 0.50 mole of hydrogen and 1.0 mole of sulfur are heated to 87^∘C in 1.0 L vessel , the following equilibrium is established H2 ​(g) + S(s) ⇌ H2S(g) , what will be the partial pressure of H2S at equilibrium? ,