kB = 1.38×10^−23JK−1. If the average speed of nitrogen molecule is 675 ms^−1. The time taken by the molecule between two successive collisions is

Sahay Sir > Question Answers > kB = 1.38×10^−23JK−1. If the average speed of nitrogen molecule is 675 ms^−1. The time taken by the molecule between two successive collisions is
Calculate the means free path of nitrogen molecule at 27∘C when pressure is 1.0 atm. Given, diameter of nitrogen molecule = 1.5Å, kB = 1.38×10^−23JK−1. If the average speed of nitrogen molecule is 675 ms^−1. The time taken by the molecule between two successive collisions is
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Calculate the means free path of nitrogen molecule at 27∘C when pressure is 1.0 atm. Given, diameter of nitrogen molecule = 1.5Å, kB = 1.38×10^−23JK−1. If the average speed of nitrogen molecule is 675 ms^−1. The time taken by the molecule between two successive collisions is Calculate the means free path of nitrogen molecule at [...]
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Tags: Calculate the means free path of nitrogen molecule at 27∘C when pressure is 1.0 atm. Given , diameter of nitrogen molecule = 1.5Å , kB = 1.38×10^−23JK−1. If the average speed of nitrogen molecule is 675 ms^−1. The time taken by the molecule between two successive collisions is ,