K = 9 × 10^9Nm^2/C^2)

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An α-particle having kinetic energy 5 MeV falls on a Cu-foil. The shortest distance from the nucleus of Cu to which α- particle reaches is (Atomic no. of Cu=29,K = 9 × 10^9Nm^2/C^2)
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An α-particle having kinetic energy 5 MeV falls on a Cu-foil. The shortest distance from the nucleus of Cu to which α- particle reaches is (Atomic no. of Cu=29,K = 9 × 10^9Nm^2/C^2) An α-particle having kinetic energy 5 MeV falls on a Cu-foil. The shortest distance from the nucleus of Cu to which α- [...]
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