In the relation y = r sin (omega t – kx)

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In the relation y = r sin (omega t – kx), the dimensions of omega/k are
15
Sep
In the relation y = r sin (omega t – kx), the dimensions of omega/k are In the relation y = r sin (omega t - kx) the dimensions of omega/k are September 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
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