In given figure from a point O in the interior of a △ABC

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In given figure from a point O in the interior of a △ABC, perpendiculars OD, OE and OF are drawn to the sides BC, CA and AB respectively. Show that : (i) AF^2 + BD^2 + CE^2 = OA^2 + OB^2 + OC^2 − OD^2 − OE^2 − OF^2 (ii) AF^2 + BD^2 + CE^2 = AE^2 + CD^2 + BF^2
05
Oct
In given figure from a point O in the interior of a △ABC, perpendiculars OD, OE and OF are drawn to the sides BC, CA and AB respectively. Show that : (i) AF^2 + BD^2 + CE^2 = OA^2 + OB^2 + OC^2 − OD^2 − OE^2 − OF^2 (ii) AF^2 + BD^2 + CE^2 [...]
Posted in: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
Tags: CA and AB respectively. Show that : (i) AF^2 + BD^2 + CE^2 = OA^2 + OB^2 + OC^2 − OD^2 − OE^2 − OF^2 (ii) AF^2 + BD^2 + CE^2 = AE^2 + CD^2 + BF^2 , In given figure from a point O in the interior of a △ABC , OE and OF are drawn to the sides BC , perpendiculars OD ,