In fig 6.48

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In fig 6.48, angle ACB = 90° and CD is perpendicular to AB. Prove that BC^2/AC^2 = BD/AD.
05
Oct
In fig 6.48, angle ACB = 90° and CD is perpendicular to AB. Prove that BC^2/AC^2 = BD/AD. angle ACB = 90° and CD is perpendicular to AB. Prove that BC^2/AC^2 = BD/AD. In fig 6.48 October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
Posted in: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
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