In Fig. 6.347
A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hands of a person standing in the car. The car is moving with constant acceleration a directed horizontally
29
Sep
A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hands of a person standing in the car. The car is moving with constant acceleration a directed horizontally In Fig. 6.347 the acceleration of A is aA = 15i + 15j. Then the [...]
In Fig. 6.347, the acceleration of A is aA = 15i + 15j. Then the acceleration of B is
29
Sep
In Fig. 6.347, the acceleration of A is aA = 15i + 15j. Then the acceleration of B is In Fig. 6.347 the acceleration of A is aA = 15i + 15j. Then the acceleration of B is September 29, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,