If you carry out the integral of the electric field ∫E→.d→l for a closed path like that as shown in (Fig. 3.40)

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If you carry out the integral of the electric field ∫E→.d→l for a closed path like that as shown in (Fig. 3.40), the integral will always be equal tom zero, independent of the shape of the path and independent of where charges may be located relative to the path. Explain why.
01
Nov
If you carry out the integral of the electric field ∫E→.d→l for a closed path like that as shown in (Fig. 3.40), the integral will always be equal tom zero, independent of the shape of the path and independent of where charges may be located relative to the path. Explain why. If you carry out [...]
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Tags: If you carry out the integral of the electric field ∫E→.d→l for a closed path like that as shown in (Fig. 3.40) , independent of the shape of the path and independent of where charges may be located relative to the path. Explain why. , the integral will always be equal tom zero ,