If d[NH3]/dt = 2 × 10^-4 mol L^-1s^-1

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For the reaction: N2 + 3H2→ 2NH3 ,If d[NH3]/dt = 2 × 10^-4 mol L^-1s^-1 , the value of -d[H2]/dt would be:
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For the reaction: N2 + 3H2→ 2NH3 ,If d[NH3]/dt = 2 × 10^-4 mol L^-1s^-1 , the value of -d[H2]/dt would be: For the reaction: N2 + 3H2→ 2NH3 If d[NH3]/dt = 2 × 10^-4 mol L^-1s^-1 the value of -d[H2]/dt would be: June 26, 2021 Category: Chapter 17 - Chemical Kinetics , Chemistry , [...]
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