If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays

Sahay Sir > Question Answers > If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays
If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays, then resulting nucleus is
28
Nov
If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays, then resulting nucleus is If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays then resulting nucleus is November 28, 2020 Category: AIIMS Last 24 Years Solved 1996 - 2019 Physics and Chemistry Video Solutions , Chapter 31 - Nuclei , Physics ,
Posted in: AIIMS Last 24 Years Solved 1996 - 2019 Physics and Chemistry Video Solutions , Chapter 31 - Nuclei , Physics ,
Tags: If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays , then resulting nucleus is ,