I2(aq) + l(aq)⇔I3(aq) This reaction is set-up in aqueous medium. We started with 1 mole of I2 and 0.5 mole of 1 in 1L flask. After equilibrium reached

Sahay Sir > Question Answers > I2(aq) + l(aq)⇔I3(aq) This reaction is set-up in aqueous medium. We started with 1 mole of I2 and 0.5 mole of 1 in 1L flask. After equilibrium reached
I2(aq) + l(aq)⇔I3(aq) This reaction is set-up in aqueous medium. We started with 1 mole of I2 and 0.5 mole of 1 in 1L flask. After equilibrium reached, excess of AgNO3 gave 0.25 mole of yellow precipitate. Equilibrium constant is
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I2(aq) + l(aq)⇔I3(aq) This reaction is set-up in aqueous medium. We started with 1 mole of I2 and 0.5 mole of 1 in 1L flask. After equilibrium reached, excess of AgNO3 gave 0.25 mole of yellow precipitate. Equilibrium constant is excess of AgNO3 gave 0.25 mole of yellow precipitate. Equilibrium constant is I2(aq) + l(aq)⇔I3(aq) [...]
Posted in: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
Tags: excess of AgNO3 gave 0.25 mole of yellow precipitate. Equilibrium constant is , I2(aq) + l(aq)⇔I3(aq) This reaction is set-up in aqueous medium. We started with 1 mole of I2 and 0.5 mole of 1 in 1L flask. After equilibrium reached ,