i.e
Example 5 In Fig 10.9, time and distance graph of a linear motion is given. Two positions of time and distance are recorded as, when T = 0, D = 2 and when T = 3, D = 8. Using the concept of slope, find law of motion, i.e., how distance depends upon time.
27
Oct
Example 5 In Fig 10.9, time and distance graph of a linear motion is given. Two positions of time and distance are recorded as, when T = 0, D = 2 and when T = 3, D = 8. Using the concept of slope, find law of motion, i.e., how distance depends upon time. D [...]
As shown in figure, when a spherical cavity (centred at O) of radius 1 is cut out of a uniform sphere of radius R (centred at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e, on the surface of the cavity. R can be determined by the equation :
23
Sep
As shown in figure, when a spherical cavity (centred at O) of radius 1 is cut out of a uniform sphere of radius R (centred at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e, on the surface of the cavity. R can be determined by the equation : [...]
3. If from an external point B of a circle with centre O, two tangents BC and BD are drawn such that ∠DBC = 120°, prove that BC + BD = BO, i.e., BO = 2BC.
05
Jul
3. If from an external point B of a circle with centre O, two tangents BC and BD are drawn such that ∠DBC = 120°, prove that BC + BD = BO, i.e., BO = 2BC. 3. If from an external point B of a circle with centre O BO = 2BC. i.e prove that [...]
49 19K isotope of potassium has a half-life of 1.4×10^9 yr and decays to form stable argon, 40 18Ar. A sample of rock has been taken which contains both potassium and argon in the ratio 1:7, i.e., (Number of potassium-14a→ms)/(Number of argon-40a→ms)=12 Assuming that when the rock was formed no argon −40 was present in the sample and none has escaped subsequently, determine the age of the rock.
05
Jun
49 19K isotope of potassium has a half-life of 1.4×10^9 yr and decays to form stable argon, 40 18Ar. A sample of rock has been taken which contains both potassium and argon in the ratio 1:7, i.e., (Number of potassium-14a→ms)/(Number of argon-40a→ms)=12 Assuming that when the rock was formed no argon −40 was present in [...]
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(Number of potassium-14a→ms)/(Number of argon-40a→ms)=12 Assuming that when the rock was formed no argon −40 was present in the sample and none has escaped subsequently ,
40 18Ar. A sample of rock has been taken which contains both potassium and argon in the ratio 1:7 ,
49 19K isotope of potassium has a half-life of 1.4×10^9 yr and decays to form stable argon ,
determine the age of the rock. ,
i.e ,
The mean life time of a radionuclide, if the activity decrease by 4% for every 1h, would b e(product is non-radioactive, i.e., stable )
05
Jun
The mean life time of a radionuclide, if the activity decrease by 4% for every 1h, would b e(product is non-radioactive, i.e., stable ) i.e if the activity decrease by 4% for every 1h stable) The mean life time of a radionuclide would b e(product is non-radioactive June 5, 2021 Category: Cengage JEE Mains Physics [...]
A positive integer is of the form 3q + 1, q being a natural number. Can you write its square in any form other than 3m + 1, i.e., 3m or 3m + 2 for some integer m? Justify your answer
22
Nov
A positive integer is of the form 3q + 1, q being a natural number. Can you write its square in any form other than 3m + 1, i.e., 3m or 3m + 2 for some integer m? Justify your answer 3m or 3m + 2 for some integer m? Justify your answer A positive [...]
A milliammeter of range 10mA and resistance 9Ω is joined in a circuit as shown. The metre gives full-scale deflection for curretn I when A and B are used as its terminals, i.e., current enters at A and leaves at B (C is left isolated). The value if I is
13
Nov
A milliammeter of range 10mA and resistance 9Ω is joined in a circuit as shown. The metre gives full-scale deflection for curretn I when A and B are used as its terminals, i.e., current enters at A and leaves at B (C is left isolated). The value if I is A milliammeter of range 10mA [...]
The energies E1 and E2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths, i.e., λ1 and λ2 will be.
12
Nov
The energies E1 and E2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths, i.e., λ1 and λ2 will be. i.e The energies E1 and E2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths λ1 and λ2 will be. November 12, 2020 [...]
The circuit shown in the figure continues to infinity. The potential difference between points 1 and 2 is V2, that between points 3 & 4 is V/4 and so on , i.e., the potential difference becomes 1/2 after every step of the ladder. Find the ratio C1/C2
10
Nov
The circuit shown in the figure continues to infinity. The potential difference between points 1 and 2 is V2, that between points 3 & 4 is V/4 and so on , i.e., the potential difference becomes 1/2 after every step of the ladder. Find the ratio C1/C2 i.e that between points 3 & 4 is [...]
Two point charges q1andq2 are placed in an external uniform electric field as shown in figure. The potential at the location of q1andq2 are V1andV2, i.e., V1andV2 are potentials at location of q1andq2 due to external unspecified charges only. Then electric potential energy for this configuration of two charged particle is
06
Nov
Two point charges q1andq2 are placed in an external uniform electric field as shown in figure. The potential at the location of q1andq2 are V1andV2, i.e., V1andV2 are potentials at location of q1andq2 due to external unspecified charges only. Then electric potential energy for this configuration of two charged particle is i.e Two point charges [...]
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i.e ,
Two point charges q1andq2 are placed in an external uniform electric field as shown in figure. The potential at the location of q1andq2 are V1andV2 ,
V1andV2 are potentials at location of q1andq2 due to external unspecified charges only. Then electric potential energy for this configuration of two charged particle is ,