g=10 m/s^(2))

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A steel ball of mass 0.1 kg falls freely from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel =460 K/kg/C,g=10 m/s^(2))
06
Sep
A steel ball of mass 0.1 kg falls freely from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel =460 K/kg/C,g=10 m/s^(2)) A steel ball of [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 13 - Thermal Expansion, Calorimetry and Transmission of Heat ,
Tags: A steel ball of mass 0.1 kg falls freely from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball , g=10 m/s^(2)) , the rise in its temperature is (specific heat of steel =460 K/kg/C ,