For the reaction : C2 ​H6 (g) ⇌ C2H4(g)+H2(g) Kp ​ is 5×10^−2 atm. Calculate the mole percent of C2 ​H6 ​(g) at equilibrium if pure C2 ​H6 at 1 atm is passed over a suitable catalyst at 900K:

Sahay Sir > Question Answers > For the reaction : C2 ​H6 (g) ⇌ C2H4(g)+H2(g) Kp ​ is 5×10^−2 atm. Calculate the mole percent of C2 ​H6 ​(g) at equilibrium if pure C2 ​H6 at 1 atm is passed over a suitable catalyst at 900K:
For the reaction : C2 ​H6 (g) ⇌ C2H4(g)+H2(g) Kp ​ is 5×10^−2 atm. Calculate the mole percent of C2 ​H6 ​(g) at equilibrium if pure C2 ​H6 at 1 atm is passed over a suitable catalyst at 900K:
11
Nov
For the reaction : C2 ​H6 (g) ⇌ C2H4(g)+H2(g) Kp ​ is 5×10^−2 atm. Calculate the mole percent of C2 ​H6 ​(g) at equilibrium if pure C2 ​H6 at 1 atm is passed over a suitable catalyst at 900K: For the reaction : C2 ​H6 (g) ⇌ C2H4(g)+H2(g) Kp ​ is 5×10^−2 atm. Calculate the [...]
Posted in: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
Tags: For the reaction : C2 ​H6 (g) ⇌ C2H4(g)+H2(g) Kp ​ is 5×10^−2 atm. Calculate the mole percent of C2 ​H6 ​(g) at equilibrium if pure C2 ​H6 at 1 atm is passed over a suitable catalyst at 900K: ,