For the equilibrium: LiCl.3NH3(s)⇔LiCl.NH3(s)+2NH3

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For the equilibrium: LiCl.3NH3(s)⇔LiCl.NH3(s)+2NH3, Kp = 9atm^2 at 37∘C. A 5 litre vessel contains 0.1 mole of LiCl.NH3. How many mole of NH3 should be added to the flask at this temperature to derive the backward reaction for completion?
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Nov
For the equilibrium: LiCl.3NH3(s)⇔LiCl.NH3(s)+2NH3, Kp = 9atm^2 at 37∘C. A 5 litre vessel contains 0.1 mole of LiCl.NH3. How many mole of NH3 should be added to the flask at this temperature to derive the backward reaction for completion? For the equilibrium: LiCl.3NH3(s)⇔LiCl.NH3(s)+2NH3 Kp = 9atm^2 at 37∘C. A 5 litre vessel contains 0.1 mole [...]
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Tags: For the equilibrium: LiCl.3NH3(s)⇔LiCl.NH3(s)+2NH3 , Kp = 9atm^2 at 37∘C. A 5 litre vessel contains 0.1 mole of LiCl.NH3. How many mole of NH3 should be added to the flask at this temperature to derive the backward reaction for completion? ,