E→1andE→2(both horizontal) have magnitudes of 2.50×10^4NC−1 and 7.00×10^4NC−1. respectively. Assuming that no other electric field lines cross the surfaces of the parallelopiped
Sahay Sir > Question Answers > E→1andE→2(both horizontal) have magnitudes of 2.50×10^4NC−1 and 7.00×10^4NC−1. respectively. Assuming that no other electric field lines cross the surfaces of the parallelopiped
The electric field E→1 at one face of a parallelopiped is uniform over the entire face and is directed out of the face. At the opposite face, the electric field E→2 is also uniform over the entire face and is directed into that face (as shown in figure). The two faces in question are inclined at 30∘ from the horizontal, E→1andE→2(both horizontal) have magnitudes of 2.50×10^4NC−1 and 7.00×10^4NC−1. respectively. Assuming that no other electric field lines cross the surfaces of the parallelopiped, the net charge contained with in is
06
Dec
The electric field E→1 at one face of a parallelopiped is uniform over the entire face and is directed out of the face. At the opposite face, the electric field E→2 is also uniform over the entire face and is directed into that face (as shown in figure). The two faces in question are inclined [...]
Tags:
E→1andE→2(both horizontal) have magnitudes of 2.50×10^4NC−1 and 7.00×10^4NC−1. respectively. Assuming that no other electric field lines cross the surfaces of the parallelopiped ,
The electric field E→1 at one face of a parallelopiped is uniform over the entire face and is directed out of the face. At the opposite face ,
the electric field E→2 is also uniform over the entire face and is directed into that face (as shown in figure). The two faces in question are inclined at 30∘ from the horizontal ,
the net charge contained with in is ,