Example 13 Find the vector equation of the plane which is at a distance of 6/sqrt 29 from the origin and its normal vector from the origin is 2i – 3j + 4k.

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Example 13 Find the vector equation of the plane which is at a distance of 6/sqrt 29 from the origin and its normal vector from the origin is 2i – 3j + 4k.
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Nov
Example 13 Find the vector equation of the plane which is at a distance of 6/sqrt 29 from the origin and its normal vector from the origin is 2i – 3j + 4k. Example 13 Find the vector equation of the plane which is at a distance of 6/sqrt 29 from the origin and its [...]
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