E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is V A −V B =10 V.

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In the circuit shown in figure, E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is V A −V B =10 V.

Nov

In the circuit shown in figure, E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is V A −V B =10 V. E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is [...]

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E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is V A −V B ​ =10 V.

E1 and E2 are two ideal sources of unknown emfs. Some currents are shown. Potential difference appearing across 6Ω resistance is V A −V B =10 V.