DM perpendicular BC and DN perpendicular AB. Prove that: (i) DM^2 =DN.MC (ii) DN^2 = DM.AN.

Sahay Sir > Question Answers > DM perpendicular BC and DN perpendicular AB. Prove that: (i) DM^2 =DN.MC (ii) DN^2 = DM.AN.
In fig. 6.57, D is a point on hypotenuse AC of triangle ABC, such that BD perpendicular AC, DM perpendicular BC and DN perpendicular AB. Prove that: (i) DM^2 =DN.MC (ii) DN^2 = DM.AN.
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Oct
In fig. 6.57, D is a point on hypotenuse AC of triangle ABC, such that BD perpendicular AC, DM perpendicular BC and DN perpendicular AB. Prove that: (i) DM^2 =DN.MC (ii) DN^2 = DM.AN. D is a point on hypotenuse AC of triangle ABC DM perpendicular BC and DN perpendicular AB. Prove that: (i) DM^2 [...]
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Tags: D is a point on hypotenuse AC of triangle ABC , DM perpendicular BC and DN perpendicular AB. Prove that: (i) DM^2 =DN.MC (ii) DN^2 = DM.AN. , In fig. 6.57 , such that BD perpendicular AC ,