can be expressed as y1 = a sin (10^15 pie t) and y2 = 2a sin (10^15 pie t + phi). Find the resultant amplitude if phase difference phi is

Sahay Sir > Question Answers > can be expressed as y1 = a sin (10^15 pie t) and y2 = 2a sin (10^15 pie t + phi). Find the resultant amplitude if phase difference phi is
Light waves from two coherent sources superimose at a point. The waves, at this point, can be expressed as y1 = a sin (10^15 pie t) and y2 = 2a sin (10^15 pie t + phi). Find the resultant amplitude if phase difference phi is
09
Sep
Light waves from two coherent sources superimose at a point. The waves, at this point, can be expressed as y1 = a sin (10^15 pie t) and y2 = 2a sin (10^15 pie t + phi). Find the resultant amplitude if phase difference phi is at this point can be expressed as y1 = a [...]
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Tags: at this point , can be expressed as y1 = a sin (10^15 pie t) and y2 = 2a sin (10^15 pie t + phi). Find the resultant amplitude if phase difference phi is , Light waves from two coherent sources superimose at a point. The waves ,