Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure)

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Sita is driving along a staight highway in her car. At time t = 0, when Sita is moving at 10 ms^-1 in the positive x-direction, she passes a signpost at x = 50 m. Here acceleration is a function of time: a = 2.0 ms^-2 – (1/10 ms^-3)t a. Derive expressions for her velocity and position as functions of time. b. At what time is her velocity greatest? c. What is the maximum velocity? d. Where is the car when it reaches the maximum velocity?
26
Aug
Sita is driving along a staight highway in her car. At time t = 0, when Sita is moving at 10 ms^-1 in the positive x-direction, she passes a signpost at x = 50 m. Here acceleration is a function of time: a = 2.0 ms^-2 – (1/10 ms^-3)t a. Derive expressions for her velocity [...]
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Tags: At t=0 , Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure) , Sita is driving along a staight highway in her car. At time t=0 , when Sita is moving at 10ms^-1 in the positive x-direction ,
At t = 0, a body starts from origin with some initial velocity. The displacement x(m) of the body varies with time t(s) as x = – (2/3)t^2 + 16t + 2. Find the initial velocity of the body and also find how long does the body take to come to rest? What is the acceleration of the body when it comes to rest?
26
Aug
At t = 0, a body starts from origin with some initial velocity. The displacement x(m) of the body varies with time t(s) as x = – (2/3)t^2 + 16t + 2. Find the initial velocity of the body and also find how long does the body take to come to rest? What is the [...]
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: At t=0 , Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure) ,
Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure)
26
Aug
Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure) Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure) August 26, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure) ,