and 3.25×10−2m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2kg is applied to the wire
Sahay Sir > Question Answers > and 3.25×10−2m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2kg is applied to the wire
During Searle’s experiment, zero of the Vernier scale lies between 3.20×10−2, and 3.25×10−2m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2kg is applied to the wire, the zero of the vernier scale still lies between 3.20×10−2, and 3.25×10−2m of the main scale but now the 45th division of Vernier scale coincide with one of the main scale divisions. the length of the thin metallic wire is 2 m and its cross-sectional ares is 8×10^−7 m^2. the least count of the Vernier scale is 1.0×10−5 m. the maximum percentage error in the Young’s modulus of the wire is
12
Feb
During Searle’s experiment, zero of the Vernier scale lies between 3.20×10−2, and 3.25×10−2m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2kg is applied to the wire, the zero of the vernier scale still lies between 3.20×10−2, and [...]
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and 3.25×10−2m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2kg is applied to the wire ,
as shown in the figure . The phase space diagram for one cycle of this system is ,
Consider the spring-mass system ,
During Searle's experiment ,
the zero of the vernier scale still lies between 3.20×10−2 ,
with the mass submerged in water ,
zero of the Vernier scale lies between 3.20×10−2 ,