An object is projected with a velocity of 10 m/s at an angle 45 with horizontal. The equation of trajectory followed by the projectile is y = ax−β x 2
Sahay Sir > Question Answers > An object is projected with a velocity of 10 m/s at an angle 45 with horizontal. The equation of trajectory followed by the projectile is y = ax−β x 2
An object is projected with a velocity of 10 m/s at an angle 45 with horizontal. The equation of trajectory followed by the projectile is y = ax−β x 2, the ratio α/β is An object is projected with a velocity of 10 m/s at an angle 45 with horizontal. The equation of trajectory followed [...]