an ac voltage E=E 0 ​ sin(ωt+ϕ) is applied and current in the circuit was found to be I = I 0 ​ sin[ ωt+ϕ+(π/4) ]. Then the unknown elements in the box may be

Sahay Sir > Question Answers > an ac voltage E=E 0 ​ sin(ωt+ϕ) is applied and current in the circuit was found to be I = I 0 ​ sin[ ωt+ϕ+(π/4) ]. Then the unknown elements in the box may be
In a black box of unknown elements (L or R or any other combination), an ac voltage E=E 0 ​ sin(ωt+ϕ) is applied and current in the circuit was found to be I = I 0 ​ sin[ ωt+ϕ+(π/4) ]. Then the unknown elements in the box may be
27
Oct
In a black box of unknown elements (L or R or any other combination), an ac voltage E=E 0 ​ sin(ωt+ϕ) is applied and current in the circuit was found to be I = I 0 ​ sin[ ωt+ϕ+(π/4) ]. Then the unknown elements in the box may be an ac voltage E=E 0 ​ [...]
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Tags: an ac voltage E=E 0 ​ sin(ωt+ϕ) is applied and current in the circuit was found to be I = I 0 ​ sin[ ωt+ϕ+(π/4) ]. Then the unknown elements in the box may be , In a black box of unknown elements (L or R or any other combination) ,