AL⊥DC. Prove that (i) ar (ABCD) = ar (EFCD) (ii) ar (ABCD) = DC × AL

Sahay Sir > Question Answers > AL⊥DC. Prove that (i) ar (ABCD) = ar (EFCD) (ii) ar (ABCD) = DC × AL
Example 1 : In Fig. 9.13, ABCD is a parallelogram and EFCD is a rectangle. Also, AL⊥DC. Prove that (i) ar (ABCD) = ar (EFCD) (ii) ar (ABCD) = DC × AL
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Example 1 : In Fig. 9.13, ABCD is a parallelogram and EFCD is a rectangle. Also, AL⊥DC. Prove that (i) ar (ABCD) = ar (EFCD) (ii) ar (ABCD) = DC × AL ABCD is a parallelogram and EFCD is a rectangle. Also AL⊥DC. Prove that (i) ar (ABCD) = ar (EFCD) (ii) ar (ABCD) = [...]
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Tags: ABCD is a parallelogram and EFCD is a rectangle. Also , AL⊥DC. Prove that (i) ar (ABCD) = ar (EFCD) (ii) ar (ABCD) = DC × AL , Example 1 : In Fig. 9.13 ,