AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2
Sahay Sir > Question Answers > AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2
Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m about the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string ( from the tip of her rod to the fly ) is taut, how much string does she have out ( see given figure)? If she pulls the string at the rate of 5 cm per second, what will the horizontal distance of the fly from her after 12 second?
05
Oct
Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m about the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string [...]
In Fig. 6.60 , AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2
05
Oct
In Fig. 6.60 , AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2 AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2 In Fig. 6.60 October 5, 2020 Category: Chapter 6 [...]