ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB^2 = BC × BD (ii) AC^2 = BC × DC (iii) AD^2 = BD × CD

Sahay Sir > Question Answers > ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB^2 = BC × BD (ii) AC^2 = BC × DC (iii) AD^2 = BD × CD
In figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB^2 = BC × BD (ii) AC^2 = BC × DC (iii) AD^2 = BD × CD
05
Oct
In figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB^2 = BC × BD (ii) AC^2 = BC × DC (iii) AD^2 = BD × CD ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB^2 = BC × BD (ii) [...]
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