ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar(△ACB) = ar(△ACF) (ii) ar(AEDF) = ar(ABCDE)

Sahay Sir > Question Answers > ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar(△ACB) = ar(△ACF) (ii) ar(AEDF) = ar(ABCDE)
11. In Fig. 9.27, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar(△ACB) = ar(△ACF) (ii) ar(AEDF) = ar(ABCDE)
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Oct
11. In Fig. 9.27, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar(△ACB) = ar(△ACF) (ii) ar(AEDF) = ar(ABCDE) 11. In Fig. 9.27 ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar(△ACB) = [...]
Posted in: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 ,
Tags: 11. In Fig. 9.27 , ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar(△ACB) = ar(△ACF) (ii) ar(AEDF) = ar(ABCDE) ,