5. In Fig. 9.8, ABCD and EFGD are two parallelograms and G is the mid-point of CD. Then ar (DPC) = 1/2 ar ( EFGD). 5. In Fig. 9.8 ABCD and EFGD are two parallelograms and G is the mid-point of CD. Then ar (DPC) = 1/2 ar ( EFGD). July 1, 2021 Category: Chapter [...]