A source S1 is producing 10^15 photons/s of wavelength 5000Å Another source S2 is producing 1.02×10^15 photons per second of wavelength 5100Å. Then (power of S_(2))/(“power of” S_(1))` is equal to

Sahay Sir > Question Answers > A source S1 is producing 10^15 photons/s of wavelength 5000Å Another source S2 is producing 1.02×10^15 photons per second of wavelength 5100Å. Then (power of S_(2))/("power of" S_(1))` is equal to
A source S1 is producing 10^15 photons/s of wavelength 5000Å Another source S2 is producing 1.02×10^15 photons per second of wavelength 5100Å. Then (power of S_(2))/(“power of” S_(1))` is equal to
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Dec
A source S1 is producing 10^15 photons/s of wavelength 5000Å Another source S2 is producing 1.02×10^15 photons per second of wavelength 5100Å. Then (power of S_(2))/(“power of” S_(1))` is equal to A source S1 is producing 10^15 photons/s of wavelength 5000Å Another source S2 is producing 1.02×10^15 photons per second of wavelength 5100Å. Then (power [...]
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