A saturated solution of Ca3 (PO4)2 has [Ca^2+ ] = 2×10^−8 M and [PO 4/3 – ]=1.6×10^−5 M of Ksp of Ca^3 (PO^4 )2 is :
Sahay Sir > Question Answers > A saturated solution of Ca3 (PO4)2 has [Ca^2+ ] = 2×10^−8 M and [PO 4/3 - ]=1.6×10^−5 M of Ksp of Ca^3 (PO^4 )2 is :
A saturated solution of Ca3 (PO4)2 has [Ca^2+ ] = 2×10^−8 M and [PO 4/3 – ]=1.6×10^−5 M of Ksp of Ca^3 (PO^4 )2 is : A saturated solution of Ca3 (PO4)2 has [Ca^2+ ] = 2×10^−8 M and [PO 4/3 - ]=1.6×10^−5 M of Ksp of Ca^3 (PO^4 )2 is : November [...]