A particle of mass 2kg moves with an initial velocity of (4iˆ+2jˆ)ms−1 on the x-y plane. A force F→=(2iˆ−8jˆ)N acts on the particle. The initial position of the particle is (2m

Sahay Sir > Question Answers > A particle of mass 2kg moves with an initial velocity of (4iˆ+2jˆ)ms−1 on the x-y plane. A force F→=(2iˆ−8jˆ)N acts on the particle. The initial position of the particle is (2m
A particle of mass 2kg moves with an initial velocity of (4iˆ+2jˆ)ms−1 on the x-y plane. A force F→=(2iˆ−8jˆ)N acts on the particle. The initial position of the particle is (2m,3m). Then for y=3m,
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A particle of mass 2kg moves with an initial velocity of (4iˆ+2jˆ)ms−1 on the x-y plane. A force F→=(2iˆ−8jˆ)N acts on the particle. The initial position of the particle is (2m,3m). Then for y=3m, 3m). Then for y=3m A particle of mass 2kg moves with an initial velocity of (4iˆ+2jˆ)ms−1 on the x-y plane. A [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) ,
Tags: 3m). Then for y=3m , A particle of mass 2kg moves with an initial velocity of (4iˆ+2jˆ)ms−1 on the x-y plane. A force F→=(2iˆ−8jˆ)N acts on the particle. The initial position of the particle is (2m ,