A particle is moving on circular path. The angle turned by radius vector is (1-e-^t/3). where θ is in radian and t is in second. The angular acceleration at t=0 is

Sahay Sir > Question Answers > A particle is moving on circular path. The angle turned by radius vector is (1-e-^t/3). where θ is in radian and t is in second. The angular acceleration at t=0 is
A particle is moving on circular path. The angle turned by radius vector is (1-e-^t/3). where θ is in radian and t is in second. The angular acceleration at t=0 is
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Oct
A particle is moving on circular path. The angle turned by radius vector is (1-e-^t/3). where θ is in radian and t is in second. The angular acceleration at t=0 is A particle is moving on circular path. The angle turned by radius vector is (1-e-^t/3). where θ is in radian and t is in [...]
Posted in: Chapter 7 - Circular Motion , MTG NEET Physics , Part 1 ,
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