A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest time it takes to reach a point a/2–√ from its mean position in seconds is
Sahay Sir > Question Answers > A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest time it takes to reach a point a/2–√ from its mean position in seconds is
Two simple harmonic are represented by the equation y1=0.1sin(100πt+π/3) and y2 = 0.1cosπt. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is at time t = 0 is
31
Oct
Two simple harmonic are represented by the equation y1=0.1sin(100πt+π/3) and y2 = 0.1cosπt. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is at time t = 0 is A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . [...]
A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest time it takes to reach a point a/2–√ from its mean position in seconds is
31
Oct
A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest time it takes to reach a point a/2–√ from its mean position in seconds is A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest [...]