Sahay Sir > Question Answers > A nuclear decay is expressed as ltbr. .6C11→.5B11+β++X Then the unknown particle X is
A nuclear decay is expressed as ltbr. .6C11 → .5B11 + β + X Then the unknown particle X is
16
Aug
A nuclear decay is expressed as ltbr. .6C11 → .5B11 + β + X Then the unknown particle X is A nuclear decay is expressed as ltbr. .6C11→.5B11+β++X Then the unknown particle X is August 16, 2020 Category: Chapter 31 - Nuclei , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video [...]