A force F=(2i^+j^​+3k^) N acts on a particle of mass 1 kg for 2s. If initial velocity of particle is u=(2j^​+i^m/s. Speed of particle at the end of 2s will be

Sahay Sir > Question Answers > A force F=(2i^+j^​+3k^) N acts on a particle of mass 1 kg for 2s. If initial velocity of particle is u=(2j^​+i^m/s. Speed of particle at the end of 2s will be
A force F=(2i^+j^​+3k^) N acts on a particle of mass 1 kg for 2s. If initial velocity of particle is u=(2j^​+i^m/s. Speed of particle at the end of 2s will be
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A force F=(2i^+j^​+3k^) N acts on a particle of mass 1 kg for 2s. If initial velocity of particle is u=(2j^​+i^m/s. Speed of particle at the end of 2s will be A force F=(2i^+j^​+3k^) N acts on a particle of mass 1 kg for 2s. If initial velocity of particle is u=(2j^​+i^m/s. Speed of particle [...]
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