A force F = (5i ^+3 j ^+2 k ^)N is applied over a particle which displaces it from its origin to the point r = (2i ^− j ^)m. The work done on the particle in joules is:

Sahay Sir > Question Answers > A force F = (5i ^+3 j ^+2 k ^)N is applied over a particle which displaces it from its origin to the point r = (2i ^− j ^)m. The work done on the particle in joules is:
A force F = (5i ^+3 j ^+2 k ^)N is applied over a particle which displaces it from its origin to the point r = (2i ^− j ^)m. The work done on the particle in joules is:
06
Dec
A force F = (5i ^+3 j ^+2 k ^)N is applied over a particle which displaces it from its origin to the point r = (2i ^− j ^)m. The work done on the particle in joules is: A force F = (5i ^+3 j ^+2 k ^)N is applied over a particle which [...]
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: A force F = (5i ^+3 j ^+2 k ^)N is applied over a particle which displaces it from its origin to the point r = (2i ^− j ^)m. The work done on the particle in joules is: ,