A charged oil drop is suspended in a uniform field of 3×10^4V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the drop is =9.9×10^−15kg and g=10m/s^2)

Sahay Sir > Question Answers > A charged oil drop is suspended in a uniform field of 3×10^4V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the drop is =9.9×10^−15kg and g=10m/s^2)
A charged oil drop is suspended in a uniform field of 3×10^4V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the drop is =9.9×10^−15kg and g=10m/s^2)
30
Nov
A charged oil drop is suspended in a uniform field of 3×10^4V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the drop is =9.9×10^−15kg and g=10m/s^2) A charged oil drop is suspended in a uniform field of 3×10^4V/m so that it neither falls nor rises. [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 17 - Electric Charge and Field ,
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