A charged oil drop is suspended in a uniform field of 3×10^4 V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the charge =9.9×10^−15kg and g=10m/s^2)

Sahay Sir > Question Answers > A charged oil drop is suspended in a uniform field of 3×10^4 V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the charge =9.9×10^−15kg and g=10m/s^2)
A charged oil drop is suspended in a uniform field of 3×10^4 V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the charge =9.9×10^−15kg and g=10m/s^2)
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A charged oil drop is suspended in a uniform field of 3×10^4 V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the charge =9.9×10^−15kg and g=10m/s^2) A charged oil drop is suspended in a uniform field of 3×10^4 V/m so that it neither falls nor [...]
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