50% of the same reaction would be completed in approximately: (log 4 = 0.60

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If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in approximately: (log 4 = 0.60, log 5 = 0.69).
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Jun
If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in approximately: (log 4 = 0.60, log 5 = 0.69). 50% of the same reaction would be completed in approximately: (log 4 = 0.60 If 60% of a first order reaction was completed in 60 [...]
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