40percent of water (by mass) reacts with CO according to the equation

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One mole of H2O and one mole of CO are taken in a 10litre vessel and heated to 725 K. At equilibrium, 40percent of water (by mass) reacts with CO according to the equation, H2O(g)+CO(g)⇔H2(g)+CO2(g) Calculate the equilibrium constant for the reaction.
22
Nov
One mole of H2O and one mole of CO are taken in a 10litre vessel and heated to 725 K. At equilibrium, 40percent of water (by mass) reacts with CO according to the equation, H2O(g)+CO(g)⇔H2(g)+CO2(g) Calculate the equilibrium constant for the reaction. 40percent of water (by mass) reacts with CO according to the equation H2O(g)+CO(g)⇔H2(g)+CO2(g) [...]
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Tags: 40percent of water (by mass) reacts with CO according to the equation , H2O(g)+CO(g)⇔H2(g)+CO2(g) Calculate the equilibrium constant for the reaction. , One mole of H2O and one mole of CO are taken in a 10litre vessel and heated to 725 K. At equilibrium ,