3n terms of an A.P. be S1
3. Let the sum of n, 2n, 3n terms of an A.P. be S1, S2 and S3, respectively, show that S3 = 3(S2 – S1 )
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Oct
3. Let the sum of n, 2n, 3n terms of an A.P. be S1, S2 and S3, respectively, show that S3 = 3(S2 – S1 ) 2n 3. Let the sum of n 3n terms of an A.P. be S1 respectively S2 and S3 show that S3 = 3(S2 – S1 ) October 27, 2021 [...]